Sort Lexicographical Order of Substrings in Java

The challenge

Given two arrays of strings a1 and a2 return a sorted array r in lexicographical order of the strings of a1 which are substrings of strings of a2.

Example 1:

a1 = ["arp", "live", "strong"]

a2 = ["lively", "alive", "harp", "sharp", "armstrong"]

returns ["arp", "live", "strong"]

Example 2:

a1 = ["tarp", "mice", "bull"]

a2 = ["lively", "alive", "harp", "sharp", "armstrong"]

returns []

The solution in Java code

Option 1:

import java.util.ArrayList; import java.util.List; public class WhichAreIn { public static String[] inArray(String[] array1, String[] array2) { List<String> in = new ArrayList<>(); for (String a : array1) for (String b : array2) if (b.contains(a)) in.add(a); return in.stream().distinct().sorted().toArray(String[]::new); } }
Code language: Java (java)

Option 2:

import java.util.stream.Stream; public class WhichAreIn { public static String[] inArray(String[] array1, String[] array2) { return Stream.of(array1) .filter(x -> Stream.of(array2).anyMatch(y -> y.contains(x))) .distinct() .sorted() .toArray(String[]::new); } }
Code language: Java (java)

Option 3:

import java.util.*; public class WhichAreIn { public static String[] inArray(String[] array1, String[] array2) { List<String> result = new ArrayList<String>(); for(int i=0; i<array1.length; i++){ for(int j=0; j<array2.length; j++ ){ if(array2[j].indexOf(array1[i]) >= 0){ result.add(array1[i]); j =array2.length; } } } Collections.sort(result); return result.toArray(new String[result.size()]); } }
Code language: Java (java)

Test cases to validate our solution

import org.junit.jupiter.api.Test; import static org.junit.jupiter.api.Assertions.*; public class WhichAreInTest { @Test public void test1() { String[] a = new String[]{ "arp", "live", "strong" }; String[] b = new String[] { "lively", "alive", "harp", "sharp", "armstrong" }; String[] r = new String[] { "arp", "live", "strong" }; assertArrayEquals(r, WhichAreIn.inArray(a, b)); } @Test public void test2() { String[] a = new String[]{ "cod", "code", "wars", "ewar", "pillow", "bed", "phht" }; String[] b = new String[] { "lively", "alive", "harp", "sharp", "armstrong", "codewars", "cod", "code" }; String[] r = new String[] { "cod", "code", "ewar", "wars" }; assertArrayEquals(r, WhichAreIn.inArray(a, b)); } }
Code language: Java (java)
Tags:
Subscribe
Notify of
guest
0 Comments
Inline Feedbacks
View all comments