The challenge

Return a new array consisting of elements which are multiple of their own index in input array (length > 1).

Examples:

[22, -6, 32, 82, 9, 25] => [-6, 32, 25]

[68, -1, 1, -7, 10, 10] => [-1, 10]

[-56,-85,72,-26,-14,76,-27,72,35,-21,-67,87,0,21,59,27,-92,68] => [-85, 72, 0, 68]

The solution in Python code

Option 1:

def multiple_of_index(l):
    return [l[i] for i in range(1, len(l)) if l[i] % i == 0]

Option 2:

def multiple_of_index(arr):
    i = 1
    rst = []
    while i < len(arr):
        if arr[i] % i == 0:
            print(i)
            rst.append(arr[i])
        i += 1
    return rst

Option 3:

def multiple_of_index(arr):
    return [n for i,n in enumerate(arr[1:], 1) if n%i==0]

Test cases to validate our solution

import test
from solution import multiple_of_index

@test.describe("Fixed Tests")
def fixed_tests():
    @test.it('Basic Test Cases')
    def basic_test_cases():
        test.assert_equals(multiple_of_index([22, -6, 32, 82, 9, 25]), [-6, 32, 25])
        test.assert_equals(multiple_of_index([68, -1, 1, -7, 10, 10]), [-1, 10])
        test.assert_equals(multiple_of_index([11, -11]), [-11])
        test.assert_equals(multiple_of_index([-56,-85,72,-26,-14,76,-27,72,35,-21,-67,87,0,21,59,27,-92,68]), [-85, 72, 0, 68])
        test.assert_equals(multiple_of_index([28,38,-44,-99,-13,-54,77,-51]), [38, -44, -99])
        test.assert_equals(multiple_of_index([-1,-49,-1,67,8,-60,39,35]), [-49, 8, -60, 35])