## Introduction#

self-dividing number is a number that is divisible by every digit it contains.

For example, 128 is a self-dividing number because `128 % 1 == 0``128 % 2 == 0`, and `128 % 8 == 0`.

Also, a self-dividing number is not allowed to contain the digit zero.

Given a lower and upper number bound, output a list of every possible self dividing number, including the bounds if possible.

Example 1:

```Input:
left = 1, right = 22
Output: [1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22]
```

**Note:**The boundaries of each input argument are `1 <= left <= right <= 10000`.

## Solution#

``````# The method where all the logic lives
def selfDividingNumbers(left, right):

# An internal function
def self_dividing(n):
# loop through each `n`
for d in str(n):
# if it's the first item, or there's no remainder
if d == '0' or n % int(d) > 0:
# False
return False
# True
return True

# Create an `output` to push to
out = []
# loop through all items, from the left to the right, inclusive
for n in range(left, right + 1):
# if we get a True
if self_dividing(n):
# push to the output
out.append(n)

#Equals filter(self_dividing, range(left, right+1))
return out
``````