# Self Dividing Numbers using Python

## Introduction

self-dividing number is a number that is divisible by every digit it contains.

For example, 128 is a self-dividing number because `128 % 1 == 0``128 % 2 == 0`, and `128 % 8 == 0`.

Also, a self-dividing number is not allowed to contain the digit zero.

Given a lower and upper number bound, output a list of every possible self dividing number, including the bounds if possible.

Example 1:

```Input:
left = 1, right = 22
Output: [1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22]
```

Note:The boundaries of each input argument are `1 <= left <= right <= 10000`.

## Solution

```.wp-block-code{border:0;padding:0}.wp-block-code>div{overflow:auto}.shcb-language{border:0;clip:rect(1px,1px,1px,1px);-webkit-clip-path:inset(50%);clip-path:inset(50%);height:1px;margin:-1px;overflow:hidden;padding:0;position:absolute;width:1px;word-wrap:normal;word-break:normal}.hljs{box-sizing:border-box}.hljs.shcb-code-table{display:table;width:100%}.hljs.shcb-code-table>.shcb-loc{color:inherit;display:table-row;width:100%}.hljs.shcb-code-table .shcb-loc>span{display:table-cell}.wp-block-code code.hljs:not(.shcb-wrap-lines){white-space:pre}.wp-block-code code.hljs.shcb-wrap-lines{white-space:pre-wrap}.hljs.shcb-line-numbers{border-spacing:0;counter-reset:line}.hljs.shcb-line-numbers>.shcb-loc{counter-increment:line}.hljs.shcb-line-numbers .shcb-loc>span{padding-left:.75em}.hljs.shcb-line-numbers .shcb-loc::before{border-right:1px solid #ddd;content:counter(line);display:table-cell;padding:0 .75em;text-align:right;-webkit-user-select:none;-moz-user-select:none;-ms-user-select:none;user-select:none;white-space:nowrap;width:1%}```# The method where all the logic lives
def selfDividingNumbers(left, right):

# An internal function
def self_dividing(n):
# loop through each `n`
for d in str(n):
# if it's the first item, or there's no remainder
if d == '0' or n % int(d) > 0:
# False
return False
# True
return True

# Create an `output` to push to
out = []
# loop through all items, from the left to the right, inclusive
for n in range(left, right + 1):
# if we get a True
if self_dividing(n):
# push to the output
out.append(n)

#Equals filter(self_dividing, range(left, right+1))
return out
```Code language: Python (python)```
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