## The challenge#

Sort a linked list using insertion sort.

A graphical example of insertion sort. The partially sorted list (black) initially contains only the first element in the list.
With each iteration, one element (red) is removed from the input data and inserted in-place into the sorted list

Algorithm of Insertion Sort:

1. Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list.
2. At each iteration, insertion sort removes one element from the input data, finds the location it belongs within the sorted list, and inserts it there.
3. It repeats until no input elements remain.

Example 1:

```Input: 4->2->1->3
Output: 1->2->3->4```

Example 2:

```Input: -1->5->3->4->0
Output: -1->0->3->4->5```

``````public class ListNode {
int val;
ListNode next;
ListNode() {}
ListNode(int val) { this.val = val; }
ListNode(int val, ListNode next) { this.val = val; this.next = next; }
}
``````

## The solution in Java code#

``````class Solution {
// Create ListNode of the Minimum Integer Value
ListNode res = new ListNode(Integer.MIN_VALUE);

// Create a dummy node
ListNode dummy = res;

// Loop while next exists
while(dummy.next!=null && dummy.next.val < head.val) {
// Re-set our dummy
dummy = dummy.next;
}

//Swap two nodes