Skip to content

How to Convert Numeric Words into Numbers using Python


Using Python, we want to convert words into numbers. In this challenge, we will explore how to convert a string into an integer.

The strings simply represent the numbers in words. Let’s convert these words into numbers.


  • “one” => 1
  • “twenty” => 20
  • “two hundred forty-six” => 246
  • “seven hundred eighty-three thousand nine hundred and nineteen” => 783919

Additional Notes:

  • The minimum number is “zero” (inclusively)
  • The maximum number, which must be supported is 1 million (inclusively)
  • The “and” in e.g. “one hundred and twenty-four” is optional, in some cases it’s present and in others, it’s not
  • All tested numbers are valid, you don’t need to validate them

Test cases to convert words into numbers

Test.assert_equals(parse_int('one'), 1) Test.assert_equals(parse_int('twenty'), 20) Test.assert_equals(parse_int('two hundred forty-six'), 246)
Code language: Python (python)

The solution in Python to convert words into numbers

def parse_int(textnum, numwords={}): # create our default word-lists if not numwords: # singles units = [ "zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen", ] # tens tens = ["", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"] # larger scales scales = ["hundred", "thousand", "million", "billion", "trillion"] # divisors numwords["and"] = (1, 0) # perform our loops and start the swap for idx, word in enumerate(units): numwords[word] = (1, idx) for idx, word in enumerate(tens): numwords[word] = (1, idx * 10) for idx, word in enumerate(scales): numwords[word] = (10 ** (idx * 3 or 2), 0) # primary loop current = result = 0 # loop while splitting to break into individual words for word in textnum.replace("-"," ").split(): # if problem then fail-safe if word not in numwords: raise Exception("Illegal word: " + word) # use the index by the multiplier scale, increment = numwords[word] current = current * scale + increment # if larger than 100 then push for a round 2 if scale > 100: result += current current = 0 # return the result plus the current return result + current
Code language: plaintext (plaintext)

See also  Uppercase text in Actionscript
Notify of
1 Comment
Oldest Most Voted
Inline Feedbacks
View all comments
2 months ago

Very interesting, but I see two bugs in the code. Incomplete lines on 27 and 41. Cool approach.

Would love your thoughts, please comment.x