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How to Check for Factor in Python

The challenge

This function should test if the factor is a factor of base.

Return true if it is a factor or false if it is not.

About factors

Factors are numbers you can multiply together to get another number.

2 and 3 are factors of 6 because: 2 * 3 = 6

  • You can find a factor by dividing numbers. If the remainder is 0 then the number is a factor.
  • You can use the mod operator (%) in most languages to check for a remainder


2 is not a factor of 7 because: 7 % 2 = 1

Note: base is a non-negative number, factor is a positive number.

The solution in Python

Option 1:

def check_for_factor(base, factor): return base/factor == int(base/factor)
Code language: Python (python)

Option 2:

def check_for_factor(base, factor): return base % factor ==
Code language: Python (python)

Option 3:

check_for_factor=lambda a,b:not a%b
Code language: Python (python)

Test cases to validate our solution

import test from solution import check_for_factor @test.describe("Fixed Tests") def fixed_tests():"Should return True") def should_return_true(): test.assert_equals(check_for_factor(10, 2), True) test.assert_equals(check_for_factor(63, 7), True) test.assert_equals(check_for_factor(2450, 5), True) test.assert_equals(check_for_factor(24612, 3), True)"Should return False") def should_return_false(): test.assert_equals(check_for_factor(9, 2), False) test.assert_equals(check_for_factor(653, 7), False) test.assert_equals(check_for_factor(2453, 5), False) test.assert_equals(check_for_factor(24617, 3), False)
Code language: Python (python)

See also  Learn Golang as a Python Developer
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